var prystring = function(char, num){
    let string = '\n'
    for (let i = 1 ; i <= num; i++){
      for(let j = num; j > i; j--){
        string += " "          
      }
      for(let k = 0; k < i * 2 -1; k++){
        string += `${char}`
      }
      for(let j = num; j > i; j--){
        string += " "
      }
      string += "\n"
    }
  console.log(string)
}
  
prystring('*',5)'
    *    
   ***   
  *****  
 ******* 
*********
'var strings = function(char, num){
    let string = '\n'
    for (let i = 0 ; i < num; i++){
      for(let j = 0; j < i; j++){
        string += " "          
      }
      for(let k = 0; k < 2 * (num-i) -1; k++){
        string += `${char}`
      }
      string += "\n"
    }
  console.log(string)
}
  
strings('*',5)'
*********
 *******
  *****
   ***
    *
'

/*
Simple String Sort Function
Given two arguments, a string of characters (input) and a sort string (sortStr),
implement a simple sort function that returns the characters to sort in the order
specified by the sort string. If any characters do not appear in the sort string,
they go at…

Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.

Example 1:

Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.

Example 2:

Input: nums = [1]
Output: 1

Example 3:

Input: nums = [5,4,-1,7,8]
Output: 23

Solution:

var maxSubArray = function(nums) {
    let sum = 0;
    let maxSum = -Infinity;
    
    if(nums.length === 0) return 0;
    if(nums.length === 1) return nums[0]
    
    for(let i = 0;i<nums.length;i++){
        sum+=nums[i];
        maxSum = Math.max(maxSum,sum);
        if(sum < 0) sum = 0;
    }
    return maxSum;
};

Write a function, intersection, that takes in two arrays, a,b, as arguments. The function should return a new array containing elements that are in both of the two arrays.

You may assume that each input array does not contain duplicate elements.

const intersection = (a, b) => {
// todo
let set = new Set()
let arr = []
for( let i = 0; i < a.length; i++){
set.add(a[i])
}
for(let j = 0; j < b.length; j ++){
if (set.has(b[j])){
arr.push(b[j])
}
}
return arr
}